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t^2-60t+450=900
We move all terms to the left:
t^2-60t+450-(900)=0
We add all the numbers together, and all the variables
t^2-60t-450=0
a = 1; b = -60; c = -450;
Δ = b2-4ac
Δ = -602-4·1·(-450)
Δ = 5400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5400}=\sqrt{900*6}=\sqrt{900}*\sqrt{6}=30\sqrt{6}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-30\sqrt{6}}{2*1}=\frac{60-30\sqrt{6}}{2} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+30\sqrt{6}}{2*1}=\frac{60+30\sqrt{6}}{2} $
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